1)Find such 2 Consecutive numbers whose SUM OF DIGITS are divisible by 7.

I challenge u to find such numbers.Einstein had created the riddle.

And There is an answer to this question.For hints send me an email on atulmkamat@gmail.com

© Copyright 2016 **Atul Kamat**. All rights reserved.

Comment | 4 words

Fri, March 1st, 2013 10:11am

Please read my work.

Comment | 25 words

Fri, March 1st, 2013 4:53pm

So two consecutive numbers whose sum is divisible by 7...

3,4 and 10,11 and 17,18 and 24,25 and 31,32 and 38,39 and so on... (Just add seven to each)

Am I Right?

Comment | 39 words

Wed, March 20th, 2013 8:48am

@QuinMarie...M srry..But u didnt get the riddle..

it is 2 consecutive numbera whose Sum OF DIGITS is divisible by 7...

Eg..U took 31 and 32...

Sum of digits are 3+1=4 and 3+2=5...where 4 and 5 are nt divisible by 7

Try it..

Posted: Mar 1, 2013

Comment | 37 words

Fri, March 1st, 2013 8:46pm

@QuinMarie...M srry..But u didnt get the riddle..

it is 2 consecutive numbera whose Sum OF DIGITS is divisible by 7...

Eg..U took 31 and 32...

Sum of digits are 3+1=4 and 3+2=5...where 4 and 5 are nt divisible by 7

Try it..

Comment | 17 words

Fri, March 1st, 2013 8:48pm

Okayy 1 hint ..There is only 2 numbers which r consecutive and whose sum of digits is divisible by 7...

Comment | 14 words

Mon, March 4th, 2013 8:14pm

Its impossible...I trued it in all the ways....Plz give me a hint

Comment | 5 words

Mon, March 4th, 2013 8:14pm

This is soooo damn tough

Comment | 16 words

Mon, April 1st, 2013 12:22pm

hey what about 7 and 7

*i didn't really get it so excuse me if my answers stupid*

Comment | 6 words

Tue, September 10th, 2013 7:09am

M sorry..But it is.. :P

Comment | 2 words

Tue, September 10th, 2013 7:09am

So Noone??

Comment | 33 words

Thu, November 7th, 2013 3:02am

Well...there is no buzz about this..anymore

So here is the answer

The 2 consecutive numbers are:

69999

70000

Where sum of digits of 69999 adds up to 42

And 70000 .. 7!!

So here 42 and 7 both are divisible by 7

jeenu1234